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Reply to "Right tire hitting the fender in the front"

@marlinjack posted:

Thank You!!

I read somewhere...concerning the 'LaMans 24 HR Race'. After attaining a top speed of 235 MPH on the Mussane (SP?) Straight, and approaching the Mussane Corner, the Brakes must 'Decelerate' 2,500,000.00 LB/FT (Yes, That's 2-1/2 Million Lb/Ft) of Rotational Torque. And the Rotors Glow Red-Hot, every Lap for 24 Hrs. I do not know how much speed they must reduce to navigate the 'Corner'. Of course, that's on 4 Rotors, all Red Hot.

Notice the Torque Measured Taken OFF from a Rotating Device, as in a Brake Rotor or Flywheel on a Dynamometer, is Labeled in 'Pound/Feet'. and Torque Applied TO A Device, such as Human 'Levering' a Torque Wrench, is in Foot/Pounds (Ft/Lbs).

Being an Engineer, you already know this. I posted this here because I read a Lot from Members, who seem to be confused on this Matter. There is the Difference.

MJ

My apologies for high-jacking the thread! Not really.

A torque is expressed in lb.ft or ft.lb (m.N or N.m in the international system), not in lb/ft nor in ft/lb since it is a force multiplied by a length, or in a multiplication the order of terms does not matter, unlike divisions, hence the possibility of using both forms.
To brake a car, it is effectively necessary to dissipate the kinetic energy of translation of the total mass of the car plus that of rotation of everything that rotates in the car and all this energy is transformed into heat produced by the friction of the pads on the discs and a bit through the engine with the throttle closed.


At the 24 hours of Le Mans, it's the Hunaudières straight and the Mulsane corner . It seems to me that they run the corner at around 110 or 120 km/h (around 70 MPH) hence the very, very, heavy braking.

Apart from the race, the Hunaudières straight is a normal road open to traffic, I drove on it several times, but at 90 km/h (55MPH) because the speed is limited and there are often the police  .

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